Glorious Math guru's, please shower me with your superior intellect. A ball is thrown down at 20ms^-1 speed from the top of a building. The building is 125 meters tall. The distance travelled before it reaches the ground is as follows: S=U0t + 1/2gt^2 U0 = 20ms^-1 g = 10ms^-2 t= time a) Find the time for the ball to drop a fifth of the height of the building b) Find the time for the ball to reach the ground Now, i feel fairly confident that i have solved this myself. Having converted this into a quadratic equation i have: a) t = 1s B) t = 3.385s However, when checking my answer against an online caluclator (https://www.calculatorsoup.com/calculators/physics/displacement_v_a_t.php) it states the answer is a complex conjugate. Now, i'm struggling to see how they have come up with a complex number here (i thought for it to be a complex number, the number you find the square root of (#^2- 4ac) had to be negative ie J = -1) but part of the course i am doing does involve complex numbers and i'm slightly worried they are trying to catch you out a bit. Any help for a dunce would be appreciated.